Answer One: The Football Cousins
Original Problem
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The linebacker wore No. 43 (clue 4). The cousin in the No. 13 shirt wasn’t the running back (clue 3) or offensive linesman (5), so the quarterback’s shirt had No. 23 and the wide receiver’s blue shirt had No. 13. The quarterback supports the Blue Sox (4). The running back supports the Jetstars (3). The man in green, who supports the Dolphins, isn’t the offensive linesman (5), so the offensive linesman’s shirt had No. 53. The running back thus wore No. 33, thus his shirt isn’t white (1) or orange (3), so yellow. The quarterback’s shirt was orange (3). The offensive linesman thus wore white. He doesn’t support the Eagles (1), so the Harlequins. The wide receiver supports the Eagles.
Thus:
Linebacker, No. 43, green, Dolphins;
Offensive linesman, No. 53, white, Harlequins;
Quarterback, No. 23, orange, Blue Sox;
Running back, No. 33, yellow, Jetstars;
Wide receiver, No. 13, blue, Eagles.
Answer Two: Anagrams
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SNOWDON (Wales)
MOUNT EVEREST (Nepal)
MATTERHORN (Switzerland)
MAUNA KEA (United States)
VINSON MASSIF (Antarctica)
WANDA PEAK (Argentina)
CASTLE HILL (Australia)
LION’S HEAD (South Africa)
MONTE ETNA (Italy)
SOUTH TWIN (Canada)
Category: Mountains
Answer Three: Halloween=Christmas
Original Problem
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When you use base 8 (Oct) and base ten (Dec).
Answer Four: 16 Coins
Original Problem
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If you draw a 5-pointed star with all sides of equal length, you will create a pentagon in the middle with all 5 sides of equal length. Then draw another 5 pointed star, upside-down, using the 5 points of the interior pentagon as the points of the inner star, This will give you another 5-sided pentagon in the interior of the second, smaller star.
Now, take your 16 coins and place 5 on the outside points of the outside star. Then place 5 more on the points of each of the two pentagons you have created. Finally, place the last coin in the dead center of this drawing.
The lines are as follows:
5 lines for the actual drawing of the outside star
5 lines for the actual drawing of the inside star
5 lines that start from any outside point of the outside star and go to the opposite point of the inside star, passing through 1 point of the inner pentagon, the dead center coin on the way.
Total lines: 15
Answer Five: Monkeys!
Original Problem
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3
In the following explanation assume:
spider monkey =sp
squirrel monkey = sq
howler monkey = h
If (2h+1sq) = 4sp then divide by 2 giving:
(1h+ 0.5sq) = 2sp
Therefore:
(1sq + 2sp) = (1sq + 1h + 0.5sq) = (1h + 1.5sq)
Therefore:
3h = (1h + 1.5sq)
Therefore:
2h = 1.5sq
Then multiply this all by 2, giving:
4h = 3sq