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Problem Six: Fifty

Here’s a fun game for two. The first person says a number between 1 and 10. Then the other will say a number that is at least 1 higher and at most 10 higher than the previous number. They go back and forth until one says 50 and wins. What’s the winning strategy for the person who starts?

One Response to “Problem Six: Fifty”

  1. on 27 Oct 2006 at 7:09 pm tony

    Not too difficult. Just work backwards.

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