Comments on: Problem One: Aliens

By: Venkat

Venkat — Mon, 08 Oct 2007 14:48:21 +0000

yea - got 4 (with Venn Diagrams)

By: mathieu

mathieu — Sat, 03 Feb 2007 05:52:20 +0000

Using venn diagram you get the exact same result, check you drawings :). Here are the groups:

2 heads only: 56
3 eyes only: 10
4 arms only: 7
9 (12-3) had two heads and three eyes (no 4 arms)
6 (9-3) had three eyes and four arms (no 2 heads)
5 (8-3) had two heads and four arms (no 3 eyes)

this one remains the same:
3 had all three unusual features.

Let’s verify the 3 first definition:
73 had two heads = 56 + 5 + 3 + 9
28 had three eyes = 10 + 6 + 3 + 9
21 had four arms = 7 + 5 + 6 + 3
…

Those groups forms a partition with total:
56
+ 10
+ 7
+ 9
+ 6
+ 5
+ 3
—-
96

By: clevi

clevi — Tue, 26 Dec 2006 04:58:05 +0000

With the help of venn diagram the alliens left with none of the above features are 13. How can we get 4 as the answer, please let me know.

By: xysk

xysk — Tue, 19 Dec 2006 18:59:51 +0000

Four.

let h=heads, e=eyes, a=arms

there are:

3 hea
9 he only (12 total he - 3hea already counted)
6 ae only ( 9 total ae - 3hea already counted)
5 ha only ( 8 total ae - 3hea already counted)
56 h only (73 total h - (3hea + 9he + 5ha)counted)
10 e only (28 total e - (3hea + 9he + 6ae)counted)
7 a only (21 total a - (3hea + 6ae + 5ha)counted)
—-
96 of 100 aliens with features. Four remain.

By: mark

mark — Sat, 18 Nov 2006 09:06:48 +0000

i think 4 is the answer.. using the venn diagram. but i think jason knows it.. difficult to explain.. ryt..

By: Jason

Jason — Fri, 17 Nov 2006 03:20:13 +0000

4 ?